A man is 24 years older than his son. In two years, his age will be twice the age of his son. The percentage age of his son is?

Answer: 22 years

Let the age of the man be x

Then the age of his son becomes (x−24)

2 years later from now,

The age of man will be = x+2

and age of his son will be =(x−24+2)=x−22

According to the question,

2(x−22)=x+2

i.e., 2x−44=x+2

i.e., x=46

Therefore,

The present age of man=46 years

And present age of his son = is 46−24 = 22 years

ND29-5-2023

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