Najma is 6 years older than her younger sister. After 10 years, the sum of their ages will be 50 years. How do you find their present ages?

Answer: 12
Explanation

Let's have R be Najma's age.

R

And we have a younger sister who is 6 years younger than Najma:

R−6

In 10 years, the sum of their ages will be 50. So in 10 years Najma will be:

R+10

and her sister will be

R−6+10

and the two added together will be 50:

(R+10)+(R−6+10)=50

How old are they now?

(R+10)+(R−6+10)=50

2R+14=50

2R=36

R=18

and her sister is

R−6=18−6=12





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MATHS MCQS (1 times)

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