John is 4 years older than David and Joe is 2 years younger than David. If the sum of their ages is 41, how old will John be in 8 years ' time?
Answer: 25
Explanation
Let's define the ages of the three people:
- Let David's age be D.
- John's age is 4 years more than David's, so John's age is D+4.
- Joe's age is 2 years less than David's, so Joe's age isD−2.
The sum of their ages is given as 41:
(D)+(D+4)+(D−2)=41
Simplify the equation:
D+D+4+D−2=41 3D+2=41Subtract 2 from both sides:
3D=39Divide both sides by 3:
D=13
So, David is 13 years old.
- John's age is D+4=13+4=17 years.
- In 8 years, John's age will be: 17+8=25 years
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