A team of 30 men is supposed to do a work in 38 days. After 25 days, 5 more men were employed and the work was finished one day earlier. How many days would it have been delayed if 5 more men were not employed?
Answer: 1 day
Explanation
35 men completed the remaining job in 12 days.
Now the same job has to be done by 30 men.
We know that, M1D1=M2D2
Required time =3035×12=14 days
Delayed time =(14−13)=1 day
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