Translational Kinetic Energy | MCQs

Q1: Which is the average translational kinetic energy of molecules in a gas at temperature 27°C?

The average translational kinetic energy of a molecule in an ideal gas is given by the formula:

$E = 3/2 k T$

Where:

Now calculate:

$E = 3 \times 1.38 \times 1 0^^{- 23} \times 300$ $E = 3/2 \times 4.14 \times 1 0^^{- 21}$

$6.21 \times 1 0^^{- 21} J$

✅ Correct: 0 | ❌ Wrong: 0 | 📊 Total Attempted: 0