Equations of Motion | MCQs
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A. distance_moved = (initial_velocity x time) + (0.5 x acceleration x time²)
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B. final velocity = initial_velocity + (2 x acceleration x distance moved)
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C. final_velocity = initial_velocity + (acceleration x time)
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D. final_velocity² = initial_velocity² + (2 x acceleration x distance moved)
Explanation
The odd one out is: final velocity = initial_velocity + (2 x acceleration x distance moved)
The other three equations are the standard equations of uniformly accelerated motion:
- 1. v = u + at (final velocity = initial velocity + acceleration x time)
- 2. s = ut + 0.5at² (distance moved = initial velocity x time + 0.5 x acceleration x time²)
- 3. v² = u² + 2as (final velocity² = initial velocity² + 2 x acceleration x distance moved)
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A. 275 m
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B. 325 m
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C. 400 m
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D. 200 m
Explanation
If the initial velocity is 40 m/s, time is 5 seconds, and acceleration is 10 m/s2, then the distance traveled is 325.
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