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A. Minimum
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B. Negative
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C. Zero
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D. Maximum
Explanation
Electric Flux Maximum (Φ = E·A·cosθ)
- When the area vector is perpendicular to the electric field, θ = 0°, so cosθ = 1.
- Therefore, Φ = EA (maximum possible flux).
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A. Positive as well as negative
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B. Zero
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C. Maximum
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D. Minimum
Explanation
According to Gauss's Law, the net electric flux through a closed surface depends on the net charge enclosed.
If equal and opposite charges are present inside the surface, their total is zero, so the net electric flux is also zero.
بجلی کے بہاؤ کی گنتی کے لئے سطح _____ ہونی چاہئے؟
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A. Curved
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B. Inclined
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C. None of these
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D. Closed
Explanation
Electric flux through a surface is defined clearly only for a closed surface.
Gauss’s Law applies to closed surfaces to calculate total flux.
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A. 180°
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B. None of these
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C. 90°
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D. 0°
Explanation
Electric flux (Φ) is maximum when E and A are parallel, i.e., angle = 0°.
Formula: Φ = E·A·cosθ → cos(0°) = 1 gives maximum flux.
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A. None of these
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B. 1.12 X 10^5 Nm^2/C
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C. 2.45 X 10^5 Nm^2/C
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D. 3.12 X 10^5 Nm^2/C
Explanation
We know that for a Gaussian surface, flux = q/ε
Here, q = 10^-6 C and ε = 8.85 X 10^-12 C/Nm^2
Therefore, flux = 10^-6/8.85 X 10^-12
= 1.12 X 10^5 Nm^2/C.
اگر ویکٹر ایریا اور برقی میدان کے درمیان زاویہ 30∘ ہے، تو بہاؤ زیادہ سے زیادہ کب ہوگا؟
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A. √2/2
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B. √3/2
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C. 1/√2
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D. 1/2
Explanation
If the angle between the vector area and the electric field is 30∘, then the flux will be maximum when √3/2.
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