Explanation

MAWKISH (ضرورت سے زیادہ جذباتی) 

Carefree (بے پرواہ، لاپرواہ)

Explanation

We are given:

• 35 kg of spinach costs Rs. 28

• We need to find how many kg can be bought for Rs. 16

Step 1: Find cost per kg

Cost per kg==28​/35=0.8Rs/kg

Step 2: Find how many kg for Rs. 16

$$text{Kg} = frac{16}{0.8} = 20$$0.8=20

Explanation

Few and far between →  both few in number and distant
(کم تعداد میں اور دور دور ہونا)

Explanation

-1

Explanation

The University of Veterinary and Animal Sciences (UVAS), formerly known as Lahore Veterinary College,

It is a public research university located in Lahore

 Established in 1882

Explanation

Work done by 12 children in 16 days = 1 (full work)

Work done by 1 child in 16 days = 1/12

Work done by 1 child in 1 day = 1/(12 × 16) = 1/192

Work done by 8 adults in 12 days = 1

Work done by 1 adult in 12 days = 1/8

Work done by 1 adult in 1 day = 1/(8 × 12) = 1/96

Work done by 16 adults in 3 days = 16 × 3 × (1/96) = 1/2

Remaining work = 1 - 1/2 = 1/2

Now, 6 adults and 4 children work together:

Work done by 6 adults in 1 day = 6 × 1/96 = 6/96 = 1/16

Work done by 4 children in 1 day = 4 × 1/192 = 4/192 = 1/48

Total work done per day = (1/16 + 1/48) = (3 + 1)/48 = 4/48 = 1/12

Days required = (1/2) ÷ (1/12) = 6 days

Explanation

Criterion پہچان معیار,

Explanation

40 men finish the work in 25 days

Total work = 40 men * 25 days = 1000 man-days

Now, 25 men will finish the work:

1000 man-days / 25 men = 40 days

Explanation

We are given:

• Product of two numbers = 1320

• HCF (Highest Common Factor) = 6

We are asked to find the LCM (Least Common Multiple).

Key formula:

$$\text{Product of two numbers}=\text{HCF}\times \text{LCM}$$

Substitute values:

$$1320 = 6 times text{LCM}$$LCM=32061​=220

Explanation

 We are given:

• 6 kangaroos eat 6 bags in 6 days

We are asked:
How many kangaroos will eat 100 bags in 100 days?

Step 1: Understand the rate

From the first statement:

6 kangaroos eat 6 bags in 6 days.
So, 1 kangaroo eats 1 bag in 6 days.

Therefore, in 1 day, 1 kangaroo eats 1/6 of a bag.

So, in 100 days, 1 kangaroo eats:

Now, let N be the number of kangaroos needed to eat 100 bags in 100 days.

If each kangaroo eats $frac{100}{6}$/6bags in 100 days, then: