The centripetal acceleration of an object moving along a circle of radius š with an angular speed š is given by the formula _____?
Answer: š = š ā
š^2
Explanation
The centripetal acceleration of an object moving along a circle of radius š with an angular speed š is given by the formula š = š ā š^2.
This formula indicates that the centripetal acceleration is directly proportional to the radius and the square of the angular speed.
This question appeared in
Past Papers (1 times)
MDCAT Past Papers and Syllabus (1 times)
This question appeared in
Subjects (1 times)
EVERYDAY SCIENCE (1 times)
Related MCQs
- A particle is moving in a uniform circular motion with constant speed v along a circle of radius r. The acceleration of the particle is?
- When the mass of a body moving along a circle becomes half and radius becomes double, and v is constant, the centripetal force becomes?
- An object moving in a circle at constant speed ______?
- If the radius is doubled, the effect on tangential acceleration depends on the type of motion. Assuming the angular velocity remains constant, if the radius is doubled, the tangential acceleration will be?
- According to Newton's 2nd law, the object's acceleration and centripetal force are?
- A car is moving in a circular path at a constant speed. What provides the necessary centripetal force to keep the car moving in this path?
- The weight of an object in an elevator moving down with acceleration of 9.8 m/s² will become:
- A particle of mass 'm' is moving on a circular path of radius 'r' with velocity 'v', then centripetal force acting on it is F. if the velocity of particle increases by 2 times and radius of circular path increases by 4 times then new centripetal force F' will be?
- A roller coaster is moving with 30 ms^-1 on a circular track of radius 30m. The net mass of coaster + passengers is 'm' the centripetal force acting on it is?
- The distance traveled by a cyclist moving on a circle of radius 15 m. If he makes 3.5 revolution is ___?