The weight of an object in an elevator moving down with acceleration of 9.8 m/s² will become:
Answer: Zero
Explanation
When the elevator accelerates downward with acceleration equal to gravity (g = 9.8 m/s²), the apparent weight becomes:
W' = m(g - a) = m(9.8 - 9.8) = 0
So, the object becomes weightless.
This question appeared in
Past Papers (2 times)
Pakistan Navy Past Papers & Jobs (2 times)
Related MCQs
- The weight of a man in an elevator descending with an acceleration of 4.9 ms⁻² will become?
- The apparent weight of man moving upward with acceleration g is ______?
- The centripetal acceleration of an object moving along a circle of radius 𝑟 with an angular speed 𝜔 is given by the formula _____?
- The apparent weight of the person when the elevator accelerating downwards is ______?
- The ratio of the weight of a man in a stationary lift and in a lift accelerating downward with uniform acceleration ‘a’ is 3:2. The acceleration of the lift is _____?
- An object descends vertically at constant velocity in sea. The three forces acting on the object are viscous drag upthrust and weight. Which relationship between their magnitude is correct?
- At the highest point what will be the acceleration of an object?
- A free-falling object has an acceleration of _______?
- According to Newton's 2nd law, the object's acceleration and centripetal force are?
- What do friction forces between the air and a moving object cause?
