A particle executing simple harmonic motion of amplitude 5 cm has maximum speed of 31.4 cm/s. The frequency of its oscillation is ______?
Answer: 1 Hz
Explanation
To find the frequency, we can use the equation:
v_max = A * ω
where v_max = 31.4 cm/s, A = 5 cm
ω = v_max / A
= 31.4 cm/s / 5 cm
= 6.28 rad/s
Now, ω = 2 * π * f
f = ω / (2 * π)
= 6.28 rad/s / (2 * π)
= 1 Hz
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