A particle of mass 40 g executes a simple harmonic motion of amplitude 2.0 cm. If the time period is 0.20 s, find the total mechanical energy of the system?
Answer: 8.0 × 10^-3 J
Explanation
Total mechanical energy (E) = (1/2) × m × ω^2 × A^2
ω = 2π / T = 2π / 0.20 s = 10π rad/s
m = 40 g = 0.04 kg
A = 2.0 cm = 0.02 m
E = (1/2) × 0.04 kg × (10π rad/s)^2 × (0.02 m)^2
= 8.0 × 10^-3 J
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