Calculate the number of photons, from green light of mercury (ʎ = 4961 Å), required to do one joule of work?
Answer: 2.4961×10^18/m^3
Explanation
Energy of one photon (E) = hc / λ
h = 6.626 × 10^-34 Js
c = 3 × 10^8 m/s
λ = 4961 Å = 4961 × 10^-10 m
E = (6.626 × 10^-34 Js × 3 × 10^8 m/s) / (4961 × 10^-10 m)
= 4.007 × 10^-19 J
Number of photons required to do 1 J of work:
n = 1 J / (4.007 × 10^-19 J)
= 2.4961 × 10^18
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