The average translational kinetic energy of O2 (relative molar mass 32) molecules at a particular temperature is 0.048eV. The translational kinetic energy of N2 (relative molar mass 28) molecules in eV at that same temperature is?
Answer: 0.048
Explanation
The average translational kinetic energy of a molecule is given by:
(3/2)kT = (3/2) × (1.38 × 10^-23 J/K) × T
Since the temperature is the same for both O2 and N2 molecules, the average translational kinetic energy will be the same:
0.048 eV = (3/2)kT
The mass of the molecule does not affect the average translational kinetic energy.
Therefore, the translational kinetic energy of N2 molecules at the same temperature is also:
0.048 eV
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