What is the kinetic energy of a bullet of mass 0.03 kg traveling at a speed of 400 m/s?
Answer: 2400 J
Explanation
KE = 1/2mv²
Given m = 0.03 kg, v = 400 m/s
KE = 1/2 × 0.03 × 400 × 400
= 1/2 × 0.03 × 160000
= 1/2 × 4800
= 2400 J
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