A rectangle WXYZ is 60 m long and 40 m wide. A path is constructed towards the inner side of the rectangle that is 2.5 wide. The area of the path is?
Answer: 475 m^2
Explanation
To find the area of the path, we need to find the area of the larger rectangle and subtract the area of the smaller rectangle.
Area of larger rectangle = Length × Width
= 60 × 40
= 2400 m²
Length of inner rectangle = 60 - 2 × 2.5 = 55 m
Width of inner rectangle = 40 - 2 × 2.5 = 35 m
Area of inner rectangle = 55 × 35
= 1925 m²
Area of path = Area of larger rectangle - Area of inner rectangle
= 2400 - 1925
= 475 m²
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