Given equation: 3x - 2y = 9
Substitute x = 5 into the equation:
3(5) - 2y = 9
15 - 2y = 9
Subtract 15 from both sides to isolate -2y:
-2y = 9 - 15
-2y = -6
Divide by -2 to solve for y:
y = -6 / -2
y = 3
If one root of the equation is 2, then we can factor the left-hand side of the equation as (x - 2)(x^2 - 4x + 3) = (x - 2)(x - 1)(x - 3) = 0.
This tells us that the other two roots are 1 and 3.
The cube roots of unity are:
1, ω, and ω², where:
- ω = -1/2 + (√3/2)i
- ω² = -1/2 - (√3/2)i
These are the complex cube roots of unity, and they satisfy:
1 + ω + ω² = 0
and
1 × ω × ω² = 1
A Row Matrix has only one row and multiple columns.
Identical Matrix (probably meant "Identity Matrix") → has 1s on the diagonal and 0s elsewhere (square matrix).
To simplify the expression 5x(2x-5),
we can use the distributive property to multiply each term inside the parentheses by 5x.
First, distribute 5x to both terms inside the parentheses:
5x * 2x = 10x^2
5x * -5 = -25x
Now we have:
10x^2 - 25x
Use integration by parts: Let u=x, dv=cos(x)dx
Then:
∫xcos(x)dx=xsin(x)−∫sin(x)dx=xsin(x)+cos(x)
Evaluate from 000 to π/2
= left( frac{pi}{2} cdot 1 + cosleft( frac{pi}{2} right) right) - left( 0 + cos(0) right) = frac{pi}{2} - 1=(π/2⋅1+cos(π/2))−(0+cos(0))=π/2−1
π/2−1
The expansion of (1 + x)⁵ can be found using the Binomial Theorem.
(1 + x)⁵ = 1 + 5x + 10x² + 10x³ + 5x⁴ + x⁵
Sum of coefficients = 1 + 5 + 10 + 10 + 5 + 1 = 32
Alternatively, we can find the sum by substituting x = 1:
(1 + 1)⁵ = 2⁵ = 32
Subtract 7 from both sides:
3x+7−7<22−7
3x<15
Divide both sides by 3:
x< 15/3
x<5