If one of the roots of the equation x^3−6x^2+11x−6=0 is 2, then the other two roots are?

1 and 3

0 and 4

-1 and 5

-2 and 6

If one root of the equation is 2, then we can factor the left-hand side of the equation as (x - 2)(x^2 - 4x + 3) = (x - 2)(x - 1)(x - 3) = 0.

This tells us that the other two roots are 1 and 3.