Trajectory | MCQs

Explanation

For projectile motion, two complementary angles θ and 90° - θ give the same range if the initial velocity is constant.

Since 10° + 80° = 90°, the angles 10° and 80° are complementary and will have equal ranges.

Explanation

 When a ball is thrown vertically upwards, its velocity decreases as it rises due to gravity.

At the maximum height, the velocity becomes zero before it starts to fall back down.

Explanation

Explanation

At the highest point of a projectile's motion:

- Its velocity is purely horizontal (vertical component = 0).

- Its acceleration is still vertically downward due to gravity.

So, the velocity vector is horizontal, and the acceleration vector is vertical ⇒ they are perpendicular.

∴ Angle between velocity and acceleration = 90°  

Explanation

Maximum height is reached when vertical velocity becomes zero.  

Using the kinematic equation:  

v² = u² - 2gh, with final v = 0,  

h = (vi² * sin²θ) / 2g.

Explanation

Ball falls 20m, so time taken is found using:

s = 1/2 gt²

20 = 1/2 × 10 × t²

t = 2s

Vertical velocity when it hits the ground:

v_y = gt = 10 × 2 = 20 m/s

Since it hits at 45°, v_x = v_y = 20 m/s

Explanation

Explanation

During projectile motion, the horizontal component of velocity "remains constant."

Explanation

The range (R) of a projectile is given by:

R = (u² * sin(2θ)) / g

where u is the initial velocity, θ is the projection angle, and g is the acceleration due to gravity.

R = (30² * sin(2*45)) / 10

= (900 * sin(90)) / 10

= 900 / 10

= 90 m

Explanation

Projectile motion is a type of two-dimensional motion where an object moves under the influence of gravity, with a constant acceleration of g (9.8 m/s²).

It involves a combination of horizontal motion with a constant velocity and vertical motion with a constant acceleration, resulting in a curved trajectory.