If ∪ = set of natural numbers up to 15, A = set of even numbers up to 15 and B = set of odd numbers up to 15, then find A' ∪ B'?

A ∪ B

B ∪ A

∪

None of these

Given:

∪ = {1, 2, 3, ..., 15}

A = {2, 4, 6, ..., 14}

B = {1, 3, 5, ..., 15}

A' = ∪ - A = {1, 3, 5, ..., 15} = B

B' = ∪ - B = {2, 4, 6, ..., 14} = A

A' ∪ B' = B ∪ A = ∪ (since B and A are complementary sets that together form ∪)