A student has 60% chance of passing in English and 54% chance of passing in both English and Mathematics. What is the percentage probability that he will fail in Mathematics?

Explanation

P(M)=pass in maths P(E)=pass in English P(E and M)= passing in both English and Maths Given P(E)=60%=0.6 P(E and M)=54%=0.54 M and E both events are independent then: P(E and M)=P(E)*P(M) P(M)=P(E and M)/P(E) P(M)=0.54/0.60=0.9 P(M!)= fail in maths P(M!)=1-p(M):(complement) P(M!)=1-0.9=0.1 P(M!)=10%