A box contains 8 red, 6 green and 7 blue toys. One of the toy is randomly picked, what is the probability that the toy picked is neither red nor green?
Answer: 7/21
Explanation
There are:
- 8 red toys
- 6 green toys
- 7 blue toys
The total number of toys is:
8+6+7=21toys
We are asked to find the probability that the toy picked is neither red nor green, which means it must be blue.
The number of blue toys is 7, so the probability is:
17/21=1/3
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