Three consecutive integers are listed in increasing order. If there sum is 102, what is the second integer in the list?
Three consecutive integers are listed in increasing order. If there sum is 102, what is the second integer in the list?
Explanation
the integers are consecutive, the middle integer must equal the “average”, or 102/3 = 34.
Therefore, the integers are 32, 34, and 36.
let three consecutive integers= x ,x+1,x+2 According to condition X+(x+1) +( x+2)=102 3x+ 3= 102 3x= 102-3 3x= 99 X= 99/3 X = 33 X+1= 33+1 X+1= 34 X+2= 34+2 X+2= 36 33, 34, 36 answer
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ND04-12-2022