A ladder makes an angle of 60 degree with the ground when placed against a wall. If the foot of the ladder is 2m away from the wall, then the length (in meters) is?

Explanation

In the figure, MN is the length of the ladder, which is placed against the wall AB and makes an angle of $60^{\circ}$ with the ground.
The foot of the ladder is at N, which is 2m away from the wall.
$∴ B N = 2 m$
In right-angled triangle MNB :
$c o s 60^{\circ} = \frac{B N}{M N} = \frac{2 m}{M N}$
$\Rightarrow \frac{1}{2} = \frac{2 m}{M N}$
$\Rightarrow M N = 4 m$
Therefore, the length of the ladder is 4m.