The sum of two numbers, if one number is two third of second is equal to 45. Find the smaller number?
Answer: 18
Explanation
Given that one number is two-thirds of the second:
x = (2/3)y
The sum of the two numbers is 45:
x + y = 45
Substitute x from the first equation:
(2/3)y + y = 45
Combine like terms:
(5/3)y = 45
Multiply both sides by 3:
5y = 135
Divide by 5:
y = 27
Now, find the smaller number x:
x = (2/3)y
x = (2/3) × 27
x = 18
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