'A' is twice as old as 'B'. Three year ago 'A' was three times as old as 'B' How old is 'A' now?

10 years

14 years

12 years

None of these

Let A's current age be x and B's current age be y.

Since A is twice as old as B, x = 2y.

Three years ago, A's age was x - 3 and B's age was y - 3.

Since A was three times as old as B, x - 3 = 3(y - 3).

Solving the equations, we get x = 12.

So, the correct answer is 12 years.