Zaid is six times as old his daughter Zoya. How old was Zaid when Zoya was born if the sum of their ages will be 49 In 7 years?

Answer: 25

Current Ages:
- Let Zoya’s current age be $x$
- Then, Zaid’s current age is $6 x$ (since he is six times as old as Zoya).
The sum of Ages in 7 Years:
- In 7 years, Zoya's age will be $x + 7$ and Zaid's age will be $6x + 7$ .
- The sum of their ages in 7 years will be $(x + 7) + (6 x + 7) = 49$ .

$x + 7 + 6 x + 7 = 49$ $7 x + 14 = 49$

Subtract 14 from both sides:

$7 x = 35$

Now divide by 7:

$x = 5$

So, Zoya’s current age is $5$ years and Zaid’s current age is:

$6 x = 6 \times 5 = 30$

When Zoya was born, Zaid would have been:

$30 - 5 = 25$

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