Ten years ago. A was half of B's in age. If the ratio of their present ages is 3:4, what will be the total of their present ages?
Ten years ago. A was half of B's in age. If the ratio of their present ages is 3:4, what will be the total of their present ages?
Explanation
Let's denote the present age of A as 3x and B as 4x.
Step 1: Express their ages 10 years ago
A's age 10 years ago = 3x - 10
B's age 10 years ago = 4x - 10
Step 2: Formulate the equation based on the given information
A was half of B's age 10 years ago:
3x - 10 = 1/2 * (4x - 10)
Step 3: Solve the equation
3x - 10 = 2x - 5
3x - 2x = -5 + 10
x = 5
Step 4: Find their present ages
A's age = 3x = 3 * 5 = 15
B's age = 4x = 4 * 5 = 20
Step 5: Calculate the total of their present ages
Total age = 15 + 20 = 35