Explanation

There are there ions   Na^ +(Z = 11), Mg ^+2  (Z=12) and Al^ +3 (Z=13)

The number of shells is the same in all three ions such as 2 shells 

The number of electrons in all three ions is the same such as they are 10 e. So electronic configuration is also the same

The number of protons of these three ion is different due to different atomic number 

Atomic number (Z) = number of protons in the nucleus of an atom = number of electrons in a neutral atom.

atomic no. of Na is 11

atomic no. of Mg^+2 is 12

atomic no. of Al^+3 is 13

So option "D" is correct