A pipe has a length of 1m. Determine the frequencies of the fundamental and first two harmonics if the pipe is opened at both ends. (speed of sound in air = 340 m/s).

A pipe has a length of 1m. Determine the frequencies of the fundamental and first two harmonics if the pipe is opened at both ends. (speed of sound in air = 340 m/s).

Explanation

To determine the frequencies of the fundamental and first two harmonics, we can use the formula:

f = v / (2L)

Where:

- f is the frequency of the harmonic

- v is the speed of sound in air

- L is the length of the pipe

Given that the length of the pipe is 1m and the speed of sound in air is 340 m/s, we can calculate the frequencies as follows:

For the fundamental frequency (first harmonic):

f1 = v / (2L)

= 340 m/s / (2 * 1m)

= 170 Hz

For the first overtone (second harmonic):

f2 = 2 * f1

= 2 * 170 Hz

= 340 Hz

For the second overtone (third harmonic):

f3 = 3 * f1

= 3 * 170 Hz

= 510 Hz

Therefore, the frequencies of the fundamental and first two harmonics for the pipe open at both ends are approximate:

- Fundamental frequency: 170 Hz

- First overtone: 340 Hz

- Second overtone: 510 Hz