An object is placed 20 cm from a diverging lens. If the distance between the lens and the image is 8 cm, what is the magnification?

ایک شے کو ڈائیورنگ لینس سے 20 سینٹی میٹر کے فاصلے پر رکھا جاتا ہے۔ اگر لینس اور تصویر کے درمیان فاصلہ 8 سینٹی میٹر ہے، تو اضافہ کیا ہے؟
Answer: 2/5
Explanation

Apart from the sign,

the magnification factor, m, is equal to i/o

"I" is the image distance from the lens 

"o" is the object distance.

we have m=i/o

(8cm) / (20cm)

= 2/5.


This question appeared in Past Papers (1 times)
Pakistan Civil Aviation Authority CAA Past Papers & Syllabus (1 times)
This question appeared in Subjects (2 times)
EVERYDAY SCIENCE (1 times)
MATHS MCQS (1 times)

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