In a Hardy-Weinberg population with two alleles, A and a, that are in equilibrium, the frequency of the allele a is 0.4. What is the percentage of the population that is homozygous for this allele?

Answer: 16
Explanation
  • The frequency of allele a is 0.4.
  • So the frequency of homozygous aa is calculated by squaring 0.4 (0.4² = 0.16).
  • This gives 16% of the population being homozygous for allele a.
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