In a Hardy-Weinberg population with two alleles, A and a, that are in equilibrium, the frequency of allele a is 0.2. What is the frequency of individuals with Aa genotype?

Answer: 0.32
Explanation
  • The frequency of allele A is 0.8 (1 - 0.2).
  • The frequency of heterozygous genotype (Aa) is 2pq.
  • It is 2(0.8)(0.2) = 0.32.
  • This question appeared in Subjects (1 times)
    EVERYDAY SCIENCE (1 times)

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