At which oxidatin state Cu achieves electronic configuration of Zn+2?
At which oxidatin state Cu achieves electronic configuration of Zn+2?
Explanation
Oxidation half-reaction :
Zn - 2e = Zn^2+
Reduction half-reaction :
Cu^2+ +2e = Cu
Zn donates two electrons to form Zn^2+ ion and Cu^2+ gains two electrons to form Cu metal.
Thus, Cu^2+ is the oxidant.