According to Crystal Field Theory (CFT) in a strong field, how many unpaired electrons are in [ πΉ π ( π π» 3 ) 6 ] 2 + ?
Answer: 0
Explanation
In the complexΒ Β [ πΉ π ( π π» 3 ) 6 ] ^2 +Β , iron (Fe) is in the +2 oxidation state, meaning it has aΒ Β π6Β electron configuration.
Ammonia (NHβ) is considered a strong field ligand under Crystal Field Theory (CFT), causing the electrons in theΒ π-orbitals to pair up due to the large splitting of theΒ
π-orbitals.
In a strong field environment, the electrons occupy the lower energyΒ Β π‘2πΒ orbitals first, and all six electrons pair up, leaving no unpaired electrons.
Therefore, the number of unpaired electrons is 0.
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