How many grams of CO2 can be produced by thermally decomposing 10 moles of ZnCO3(S)?
How many grams of CO2 can be produced by thermally decomposing 10 moles of ZnCO3(S)?
Explanation
The decomposition reaction is:
ZnCO 3(s)→ZnO(s)+CO 2(g) One mole of ZnCO₃ produces one mole of CO₂, so 10 moles will produce 10 moles of CO₂.
The molar mass of CO₂ is:
CO₂=12+(16×2)=44g/mol Therefore,
10 moles of CO₂=10×44=440g.