How many grams of CO2 can be produced by thermally decomposing 10 moles of ZnCO3(S)?
Answer: 440
Explanation
The decomposition reaction is:
ZnCO 3(s)→ZnO(s)+CO 2(g) One mole of ZnCO₃ produces one mole of CO₂, so 10 moles will produce 10 moles of CO₂.
The molar mass of CO₂ is:
CO₂=12+(16×2)=44g/mol Therefore,
10 moles of CO₂=10×44=440g.
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