The radioactivity due to C-14 isotope (half life 6000 years) a sample of wood from an ancient tomb was found to be nearly half of that fresh wood. The tomb is therefore about _____?
Answer: 6000 years
Explanation
If the radioactivity is half of that in fresh wood, the time elapsed is equal to one half-life of C-14, which is 6000 years.
Therefore, the tomb is approximately 6000 years old.
This question appeared in
Past Papers (4 times)
Lecturer Chemistry Past Papers and Syllabus (1 times)
SPSC 25 Years Past Papers Subject Wise (Solved) (2 times)
SPSC Past Papers (1 times)
This question appeared in
Subjects (1 times)
EVERYDAY SCIENCE (1 times)
Related MCQs
- The sample of polonium - 218 has original mass of 160 micrograms. How much of this sample will be left after three half lives?
- I've been here for over four and a half billion years. Here 'four and a half' is?
- Uranium-238 forms Thorium-234 after radioactive decay and has a half-life of 4.5 × 10^9 years. How many years will it take to decay 75% of the initial amount?
- A man covers half of his journey at 6 km/hr and the remaining half at 3 km/hr. His average speed is _____?
- A rectangular piece of wood is kept in 3 different ways (A, B, C) on a table. Pressure exerted by the wood on the table will be ____?
- Which of the following organism is found in the gut of termite and help in the digestion of wood?
- Half-life of a radioactive substance depends upon?
- The density of an object can be determined using the formula Density= Mass/Volume. The piece of wood shown has a mass of 16 grams. What is the density of the piece of wood?
- What is the period after the first half and before the second half called?
- The tomb of Anarkali is situated in _____?