What is pH of a 1 molar solution of an acid that has a Ka - 10.8?

What is pH of a 1 molar solution of an acid that has a Ka - 10.8?

Explanation
  • For a strong acid with a high KaK_a value (10.8), it fully ionizes in water.
  • pH is calculated as pH=log[H+]pH = -log[H^+], and for a 1 M strong acid, [H+]=104[H^+] = 10^{-4}, so pH = 4.