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What is pH of a 1 molar solution of an acid that has a Ka - 10.8?
What is pH of a 1 molar solution of an acid that has a Ka - 10.8?
10
8
4
None of these
Explanation
For a strong acid with a high
K
a
K_a
K
a
value (10.8)
, it fully ionizes in water.
pH is calculated as
p
H
=
−
log
[
H
+
]
pH = -log[H^+]
, and for a 1 M strong acid,
[
H
+
]
=
10
−
4
[H^+] = 10^{-4}
, so
pH = 4.