______ 0.25M NaOH and needed to neutralize 10mL of 0.50 HCL?
______ 0.25M NaOH and needed to neutralize 10mL of 0.50 HCL?
Explanation
Using the neutralization formula:
M₁V₁ = M₂V₂
Given:
- M₁ (HCl) = 0.50 M
- V₁ (HCl) = 10 mL
- M₂ (NaOH) = 0.25 M
- V₂ (NaOH) = ?
Now, solving:
(0.50 M) (10 mL) = (0.25 M) (V₂)
5 = 0.25V₂
V₂ = 20 mL