______ 0.25M NaOH and needed to neutralize 10mL of 0.50 HCL?

______ 0.25M NaOH and needed to neutralize 10mL of 0.50 HCL?

Explanation

Using the neutralization formula:
M₁V₁ = M₂V₂

Given:

  • M₁ (HCl) = 0.50 M
  • V₁ (HCl) = 10 mL
  • M₂ (NaOH) = 0.25 M
  • V₂ (NaOH) = ?

Now, solving:
(0.50 M) (10 mL) = (0.25 M) (V₂)
5 = 0.25V₂
V₂ =
20 mL