In the equilibrium mixture, the concentration of hydrogen and iodine is 0. 04 moles per dm³, while that of hydrogen iodide is 0.08 per dm³. The Kc of the following given reaction will be equal to: H₂ (g) + I₂ (g) ⇌ 2HI (g)?
Answer: 4
Explanation
To find the equilibrium constant (Kc) for the reaction H₂ (g) + I₂ (g) ⇌ 2HI (g), we use the formula:
Kc = [HI]² / [H₂] [I₂]
Given concentrations:
[HI] = 0.08 mol/dm³
[H₂] = 0.04 mol/dm³
[I₂] = 0.04 mol/dm³
Kc = (0.08)² / (0.04 × 0.04)
= 0.0064 / 0.0016
= 4
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