A wire has a resistance of 6 Ω. It is cut into two parts and both the halves are connected in parallel. The new resistance is:
ایک تار کی مزاحمت 6 اوہم ہے۔ اسے دو حصوں میں کاٹا جاتا ہے اور دونوں حصے متوازی طور پر جڑے ہوتے ہیں۔ نئی مزاحمت ہے۔
Answer: 1.5 Ω
Explanation
We are given:
A wire with resistance R = 6 Ω
It is cut into two equal parts
These two parts are then connected in parallel
Step 1:
Resistance of each half
When a wire is cut into two equal parts, the resistance of each half becomes half:
Rhalf=6/2=3Ω
Step 2:
Two 3 Ω resistors in parallel
Use the formula for two resistors in parallel:
Req1=1/3+1/3=2/3
Req=3/2=1.5Ω
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