A rectangle-shaped open-to-sky tank of water has a length of 2 m and a width of 1 m. If the atmospheric pressure is assumed 16 to be 100 kPa and thickness of the tank walls is assumed to be negligible, the force exerted by the atmosphere on the surface of water is?

Answer: 200 KN
Explanation

The force exerted by the atmosphere on the surface of the water is equal to the pressure multiplied by the area of the surface:

Force = Pressure x Area

= 100 kPa x (2 m x 1 m)

= 100,000 Pa x 2 m^2

= 200,000 N

= 200 kN

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