The de-Broglie wavelength associated with a particle moving at 10^6 m/s and having mass 10^-30 kg?
Answer: 6.6×10^-10m
Explanation
The de-Broglie wavelength (λ) is given by the formula:
λ = h / (m × v)
Where:
h = Planck's constant = 6.626 × 10^-34 J s
m = mass of the particle = 10^-30 kg
v = velocity of the particle = 10^6 m/s
Substituting the values, we get:
λ = (6.626 × 10^-34 J s) / (10^-30 kg × 10^6 m/s)
= (6.626 × 10^-34 J s) / (10^-24 kg m/s)
= 6.626 × 10^-10 m
So, the de-Broglie wavelength associated with the particle is 6.6×10^-10m.
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