A Javelin is thrown by Arshad Nadeem at projection angle of 45 degrees with initial velocity of 30 m/s, the range of the Javelin will be (consider g = 10 m/s²)?
Answer: 90m
Explanation
The range (R) of a projectile is given by:
R = (u² * sin(2θ)) / g
where u is the initial velocity, θ is the projection angle, and g is the acceleration due to gravity.
R = (30² * sin(2*45)) / 10
= (900 * sin(90)) / 10
= 900 / 10
= 90 m
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