The moment of inertia of a thin uniform disk about an axis passing through its centre and perpendicular to its plane is MR^2/2, then its M.I about a tangent parallel to its diameter is ______?
Answer: 3/2 MR^2
Explanation
Using the Parallel Axis Theorem:
I = I_CM + Md^2
where I_CM = MR^2/2 and d = R (radius)
I = MR^2/2 + MR^2
= 3/2 MR^2
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