A particle executing simple harmonic motion of amplitude 5 cm has maximum speed of 31.4 cm/s. The frequency of its oscillation is ______?

3 Hz

1 Hz

2 Hz

None of these

To find the frequency, we can use the equation:

v_max = A * ω

where v_max = 31.4 cm/s, A = 5 cm

ω = v_max / A

= 31.4 cm/s / 5 cm

= 6.28 rad/s

Now, ω = 2 * π * f

f = ω / (2 * π)

= 6.28 rad/s / (2 * π)

= 1 Hz