The hydrogen-like atom has one electron revolving around a stationary nucleus. The energy required to execute electron from the second orbit to the third orbit is 42.7eV. The atomic number of the atom is _______?
Answer: 4
Explanation
The energy required to excite an electron from the second orbit to the third orbit is:
ΔE = 13.6Z^2(1/4 - 1/9) eV
Given ΔE = 42.7 eV:
42.7 = 13.6Z^2(1/4 - 1/9)
Solving for Z:
Z = 4
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