What is the divergence of the vector field f = 3x^2i + 5xyj + xyz^3kA at the point (1, 2, 3)?
Answer: 65
Explanation
To find the divergence, calculate:
div(f) = ∂/∂x (3x^2) + ∂/∂y (5xy) + ∂/∂z (xyz^3)
= 6x + 5x + 3xyz^2
At (1, 2, 3):
div(f) = 6(1) + 5(1) + 3(1)(2)(3)^2
= 6 + 5 + 54
= 65
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