The latent heat of vaporization of water is 2,240 J. If the work done in the process of vaporization 1g is 168 J, then the increase in internal energy is?
The latent heat of vaporization of water is 2,240 J. If the work done in the process of vaporization 1g is 168 J, then the increase in internal energy is?
Explanation
To find the increase in internal energy, we can use the equation:
ΔU = Q - W
where ΔU is the change in internal energy, Q is the heat energy added (which is the latent heat of vaporization in this case), and W is the work done.
Given:
Q = 2240 J (latent heat of vaporization of water per gram)
W = 168 J (work done in the process of vaporization)
Now, we can plug in the values:
ΔU = Q - W
= 2240 J - 168 J
= 2072 J